Question

Tìm x

\(4.\left(3-x\right)-5.\left(x-1\right)=x+20\)

Answer 1

Ta có: \(4\left(3-x\right)-5\left(x-1\right)=x+20\)

\(\Leftrightarrow12-4x-5x+5-x-20=0\)

\(\Leftrightarrow-10x=3\)

hay \(x=-\dfrac{3}{10}\)

Answer 2

\(4\cdot\left(3-x\right)-5\cdot\left(x-1\right)=x+20\)

\(\Leftrightarrow-4x-5x-x=-12-5+20\)

\(\Leftrightarrow-10x=3\)

\(\Leftrightarrow x=-\dfrac{3}{10}\)