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Ta có: (1/4)*(2/6)*(3/8)*(4/10)*(5/12)*...*(30/62)*(31/64)=2^x. Tìm x
tìm x biết :
(1/4).(2/6).(3/8).(4/10).(5/12)....(30/62).(31/64) = 2^x
DT
27 tháng 3 2022 lúc 7:51
Tìm x, biết \(\dfrac{1}{4}.\dfrac{2}{6}.\dfrac{3}{8}.\dfrac{4}{10}.\dfrac{5}{12}...\dfrac{30}{62}.\dfrac{31}{64}=2^x\)
Tìm x biết:\(\frac{1}{4}.\frac{2}{6}.\frac{3}{8}...\frac{30}{62}.\frac{31}{64}=2^x\)
(x-1)x+2=(x-1)x+4
1/ 4 . 2/6 . 3/8 . 4/10 . 5/15 .... 30/62 . 31/64= 2x
1/4 x 2/6 x3/8 x 4/10 x 5/12 x....x 30/62 x 31/64=2n. Tìm n
Tìm x biết : \(\frac{1}{4}\times\frac{2}{6}\times\frac{3}{8}\times\frac{4}{10}\times.......\times\frac{30}{62}\times\frac{31}{64}=2^x\)
Tìm số nguyên n, biết rằng:
\(\dfrac{1}{4} . \dfrac{2}{6} . \dfrac{3}{8} .\dfrac{4}{10} . \dfrac{5}{12} .... \dfrac{30}{62} . \dfrac{31}{64} = 2^{n}\)\(\)
Tìm x biết rằng :
\(\frac{1}{4}.\frac{2}{6}.\frac{3}{8}.\frac{4}{10}.\frac{5}{12}...\frac{30}{62}.\frac{31}{64}=2^x\)
Thanks for helping !