\(\left|x-3y\right|^{2014}+\left|y+4\right|^{2012}=0\)
\(Do\)\(\left|x-3y\right|^{2014}\ge0\)\(;\left|y+4\right|^{2012}\ge0\)
\(\Rightarrow\orbr{\begin{cases}\left|x-3y\right|^{2014}=0\\\left|x+4\right|^{2012}=0\end{cases}\Rightarrow\orbr{\begin{cases}x=12\\y=-4\end{cases}}}\)
\(KL\)