Nếu x lớn hơn 2 thì 1003x+2y lớn hơn 3009>2008. Vậy x=1 hoặc x=2. Vì 2008-2y chẵn nên x chẵn. Vậy x=2 nên 2y=2008-2006=2. Suy ra y=1.
tim x,y nguyen duong thoa
x=can2x(x-y)+2y-x=2
tim nghiem nguyen duong: \(3^x=y^2+2y\)
tim hai so nguyen duong x,y thoa man x3 +7x = y3 +7y
a)Tim cap (x,y) nguyen duong thoa man xy=3(y-x)
b)cho 2 so x,y >0 thoa man x+y = 1
Tim GTNN cua M=(x^2+1/y^2)(y^2+1/x^2)
a)Tim tat ca cac so nguyen duong x, y , z thoa man: \(\frac{x+y\sqrt{2013}}{y+z\sqrt{2013}}\)la so huu ti, dong thoi x2 + y2+ z2 la so nguyen to.
b) Tim so tu nhien x, y thoa man: x(1+x+x2) = y(y-1).
1/ Tim x, y nguyen duong thoa man: \(y=\sqrt[3]{18+\sqrt{x+100}}+\sqrt[3]{18-\sqrt{x+100}}\)
cho cac so thuc duong x,y thoa man x+y<=3.Tim GTNN cua 1/5xy + 5/x+2y+5
tim cac so nguyen duong x;y;z thoa man \(3x^2-18y^2+2z^2+3y^2z^2-18x=27\)
Cho x,y,z nguyen duong thoa man x+y-z+1=0
Tim GTLN cua \(P=\frac{x^3y^3}{\left(x+yz\right)\left(y+xz\right)\left(z+xy\right)^2}\)