\(\left|x\right|=\dfrac{3}{8}\\ \Rightarrow\left[{}\begin{matrix}x=-\dfrac{3}{8}\\x=\dfrac{3}{8}\end{matrix}\right.\)
\(x\in\left\{\dfrac{3}{8};-\dfrac{3}{8}\right\}\)
|x|=\(\dfrac{3}{8}\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{3}{8}\\x=\dfrac{-3}{8}\end{matrix}\right.\)
Vậy x∈{\(\dfrac{3}{8}\);\(\dfrac{-3}{8}\)}
\(\left|x\right|=\dfrac{3}{8}\)
\(\Rightarrow\left[{}\begin{matrix}x=-\dfrac{3}{8}\\x=\dfrac{3}{8}\end{matrix}\right.\)
\(\left|x\right|=\dfrac{3}{8}\)
\(\Rightarrow x\in\left\{\dfrac{3}{8};\left(\dfrac{-3}{8}\right)\right\}\)