Ta có : x2 - 10x = -25
=> x2 - 2.x.5 + 52 = 0
<=> (x - 5)2 = 0
=> x - 5 = 0
=> x = 5
x2-10x = -25
=> x2 -10x +25=0
=> (x-5)2 = 0
=> x = 5
\(x^2-10x=-25\)
\(\Leftrightarrow x^2-10x+25=0\)
\(\Leftrightarrow x^2-2.5.x+5^2=0\)
\(\Leftrightarrow\left(x-5\right)^2=0\)
\(\Rightarrow x=5\)