Question

tìm x: |x-2,5| + |3,5-x|=0

Answer 1

\(\left|x-2,5\right|>=0\forall x\)

\(\left|3,5-x\right|>=0\forall x\)

Do đó: \(\left|x-2,5\right|+\left|3,5-x\right|>=0\forall x\)

Dấu '=' xảy ra khi \(\left\{{}\begin{matrix}x-2,5=0\\3,5-x=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=2,5\\x=3,5\end{matrix}\right.\)

=>Loại