a: =>\(x\in\left\{0;4;8;...\right\}\)
b: =>x+1-4 chia hết cho x+1
=>\(x+1\in\left\{1;2;4\right\}\)
=>\(x\in\left\{0;1;3\right\}\)
c: =>2x-3=7k(k\(\in N\))
=>2x=7k+3, \(k\in Z^+\)
=>\(\left\{{}\begin{matrix}k\in Z^+\\x=\dfrac{7k+3}{2}\end{matrix}\right.\)