\(\sqrt{x-2}=4\)
ĐKXĐ: \(x\ge2\)
\(\Leftrightarrow\left(\sqrt{x-2}\right)^2=16\)
\(\Leftrightarrow\left|x-2\right|=16\)
\(\Leftrightarrow x-2=16\) (Vì \(x\ge2\))
\(\Leftrightarrow x=18\) (TM)
b) \(\sqrt{x-2}< 4\)
ĐKXĐ: \(x\ge2\)
\(\Leftrightarrow\left(\sqrt{x-2}\right)^2< 16\)
\(\Leftrightarrow\left|x-2\right|< 16\)
\(\Leftrightarrow x-2< 16\)
\(\Leftrightarrow x< 18\)
Kết hợp ĐK \(\Rightarrow2\le x< 18\)