`2/x = x/50`
`=> x^2 = 50*2`
`=> x^2 = 100`
`=> x = 10 ` hoặc`x=-10`
Vậy `x∈{10 ; -10}`
`2/x = x/50`
`=> x^2 = 50*2`
`=> x^2 = 100`
`=> x = 10 ` hoặc`x=-10`
Vậy `x∈{10 ; -10}`
\(\frac{x}{50}+\frac{x-1}{49}+\frac{x-2}{48}+\frac{x-3}{47}+\frac{x-150}{25}=0\)
Tìm x
Tìm x biết :a, \(\frac{x+1}{2019}+\frac{x}{1010}+\frac{x-2}{674}+\frac{x-4}{506}+10=0\)
b, \(\frac{x}{50}-\frac{x-1}{51}=\frac{x+2}{48}-\frac{x-3}{53}\)
Tìm các số nguyên x,y thỏa mãn
2xy + 6x - y = 10
xy + 4x - 3y = 1
tìm x , y
\(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}\)và x-y+z=50
Tìm x , y , z nếu :
a)\(\frac{x+y+1}{x}=\frac{x+z+2}{y}=\frac{x+y-3}{z}=\frac{1}{x+y+z}\)
b)\(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}\)và 2x+3y-z=50
\(\frac{75}{2}-\frac{1}{50}.\left(\frac{2}{3}x-1\right)^3=24\)
Tìm x
Tìm x, biết:
\(2x-\frac{1}{2}-\frac{1}{6}-\frac{1}{12}-...-\frac{1}{49.50}=7+\frac{1}{50}+x\)
Tìm x;yE Z:
\(\frac{x}{2}=\frac{y}{3};\frac{y}{2}=\frac{z}{5}\)Và x+y+z=50
Help me:
Tìm x:
a, \(\frac{x+7}{7}+\frac{x+14}{6}=\frac{x-2008}{2016}+\frac{x+2023}{2015}\)
b, \(\frac{x+1}{8}+\frac{x+2}{7}=\frac{x}{3}-\frac{x+3}{6}\)
c, 1+\(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+.....+\frac{2}{x\cdot\left(x+1\right)}=\frac{99}{50}\)(x thuộc N*)
tìm x,y,z biết:
\(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-5}{4}\) và 2.x+3.y-z=50
Tìm x biết \(\frac{-\left(-x\right)}{5}-\frac{2}{10}=\frac{1}{-5}-\frac{7}{50}\)