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Tìm \(x\)

\(\dfrac{x-1}{13}-\dfrac{2x-13}{15}=\dfrac{3x-15}{27}-\dfrac{4x-27}{29}\)

H24
4 tháng 7 lúc 21:15

\(\dfrac{x-1}{13}-\dfrac{2x-13}{15}=\dfrac{3x-15}{27}-\dfrac{4x-27}{29}\)

\(\Rightarrow\left(\dfrac{x-1}{13}-1\right)-\left(\dfrac{2x-13}{15}-1\right)=\left(\dfrac{3x-15}{27}-1\right)-\left(\dfrac{4x-27}{29}-1\right)\)

\(\Rightarrow\dfrac{x-14}{13}-\dfrac{2\left(x-14\right)}{15}=\dfrac{3\left(x-14\right)}{27}-\dfrac{4\left(x-14\right)}{29}\)

\(\Rightarrow\dfrac{x-14}{13}-\dfrac{2\left(x-14\right)}{15}-\dfrac{3\left(x-14\right)}{27}+\dfrac{4\left(x-14\right)}{29}=0\)

\(\Rightarrow\left(x-14\right)\left(\dfrac{1}{13}-\dfrac{2}{15}-\dfrac{3}{27}+\dfrac{4}{29}\right)=0\)

\(\Rightarrow x-14=0\) (vì \(\dfrac{1}{13}-\dfrac{2}{15}-\dfrac{3}{27}+\dfrac{4}{29}\ne0\))

\(\Rightarrow x=14\)

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NT

\(\dfrac{x-1}{13}-\dfrac{2x-13}{15}=\dfrac{3x-15}{27}-\dfrac{4x-27}{29}\)

=>\(\left(\dfrac{x-1}{13}-1\right)-\left(\dfrac{2x-13}{15}-1\right)=\left(\dfrac{3x-15}{27}-1\right)-\left(\dfrac{4x-27}{29}-1\right)\)

=>\(\dfrac{x-14}{13}-\dfrac{2x-28}{15}=\dfrac{3x-42}{27}-\dfrac{4x-56}{29}\)

=>\(\left(x-14\right)\left(\dfrac{1}{13}-\dfrac{2}{15}-\dfrac{3}{27}+\dfrac{4}{29}\right)=0\)

=>x-14=0

=>x=14

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