Question

Tìm x, biết:
x²-x+(2x-2)=0

Answer 1

x²-x+(2x-2)=0
\(\Leftrightarrow\)x(x-1)+2(x-1)=0
\(\Leftrightarrow\)(x-1)(x+2)=0
\(\Leftrightarrow\)\(\left[{}\begin{matrix}x-1=0\\x+2=0\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-2\end{matrix}\right.\)
Vậy x=1 hoặc x=-2

Answer 2

\(x^2-x+\left(2x-2\right)=0\\ \Leftrightarrow x\left(x-1\right)+2\left(x-1\right)=0\\ \Leftrightarrow\left(x-1\right)\left(x+2\right)=0\\ \Rightarrow x=1;x=-2\)

Answer 3

\(\Leftrightarrow\)x(x-1)+2(x-1)=0
\(\Leftrightarrow\)(x-1)(x+2)=0
\(\Leftrightarrow\)\(\left[{}\begin{matrix}x-1=0\\x+2=0\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-2\end{matrix}\right.\)
VẬY x= 1 HOẶC x=-2