Ta có: \(x^2+x=\dfrac{3}{2}\)
=>\(x^2+x+\dfrac{1}{4}=\dfrac{3}{2}+\dfrac{1}{4}\)
=>\(\left(x+\dfrac{1}{2}\right)^2=\dfrac{7}{4}\)
=>\(\left[{}\begin{matrix}x+\dfrac{1}{2}=\dfrac{\sqrt{7}}{2}\\x+\dfrac{1}{2}=-\dfrac{\sqrt{7}}{2}\end{matrix}\right.\)
=>\(\left[{}\begin{matrix}x=\dfrac{\sqrt{7}}{2}-\dfrac{1}{2}\\x=-\dfrac{\sqrt{7}}{2}-\dfrac{1}{2}\end{matrix}\right.\)