Sửa đề: \(\left(x-3\right)^3-\left(x-3\right)\left(x^2+3x+9\right)+9\left(x+1\right)^2=15\)
=>\(x^3-9x^2+27x-27-\left(x^3-27\right)+9\left(x^2+2x+1\right)=15\)
=>\(x^3-9x^2+27x-27-x^3+27+9x^2+18x+9=15\)
=>\(45x+9=15\)
=>45x=6
=>\(x=\dfrac{6}{45}=\dfrac{2}{15}\)