=>|x-1|+|x-2|=2016
TH1: x<1
Pt sẽ là 1-x+2-x=2016
=>-2x+3=2016
=>-2x=2013
=>x=-2013/2(nhận)
TH2: 1<=x<2
Pt sẽ là x-1+2-x=2016
=>1=2016(loại)
TH3: x>=2
Pt sẽ là 2x-3=2016
=>2x=2019
=>x=2019/2(nhận)
\(x+2015\frac{1}{2}=\sqrt{1+2015^2+\frac{2015^2}{20162}}+\frac{2015}{2016}\)
Tính
\(M=\dfrac{1}{2\sqrt{1}+1\sqrt{2}}+\dfrac{1}{3\sqrt{2}+2\sqrt{3}}+.......+\dfrac{1}{2015\sqrt{2014}+2014\sqrt{2015}}\)
Chứng tỏ :
\(\dfrac{1}{\sqrt{x+2014}+\sqrt{y+2014}}-\dfrac{1}{\sqrt{2015-x}+\sqrt{2015-y}}+\dfrac{1}{\sqrt{2014-x}+\sqrt{2014-y}}\ne0\)
Chứng tỏ \(1+\dfrac{1}{\sqrt{2}}+\dfrac{1}{\sqrt{3}}+.....+\dfrac{1}{\sqrt{2015}}\le2\sqrt{2015}\)
Gợi ý : áp dụng \(\sqrt{n+1}-\sqrt{n}>\dfrac{1}{2\sqrt{n+1}}\)
Giải phương trình:
1. \(\sqrt{2x^2+4x+7}=x^4+4x^3+3x^2-2x-7\)
2. \(\dfrac{4}{x}+\sqrt{x-\dfrac{1}{x}}=x+\sqrt{2x-\dfrac{5}{x}}\)
3. \(\dfrac{6-2x}{\sqrt{5-x}}+\dfrac{6+2x}{\sqrt{5+x}}=\dfrac{8}{3}\)
4. \(x^2+1-\left(x+1\right)\sqrt{x^2-2x+3}=0\)
5. \(2\sqrt{2x+4}+4\sqrt{2-x}=\sqrt{9x^2+16}\)
6. \(\left(2x+7\right)\sqrt{2x+7}=x^2+9x+7\)
a, Tính giá trị của biểu thức A= \(\dfrac{1}{\sqrt{1}+\sqrt{2}}\) + \(\dfrac{1}{\sqrt{2}+\sqrt{3}}\) + ...... + \(\dfrac{1}{\sqrt{48}+\sqrt{49}}\)
b, Tính giá trị biểu thức B = x3 + 2013x2y - 2014y3 + 2015 biết \(\dfrac{x}{y}\)\(\sqrt{\dfrac{y}{x}}\)= \(\dfrac{y}{x}\)\(\sqrt{\dfrac{x}{y}}\)
Giải PT : \(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+...+\dfrac{1}{x\left(x+1\right)}=\dfrac{\sqrt{2017-x}+2016}{\sqrt{2016-x}+2017}\)
rút gọn A=(\(\frac{3\sqrt{x}+6}{x-4}+\frac{\sqrt{x}}{\sqrt{x}-2}\)) / \(\frac{x-9}{\sqrt{x}-3}\)
tinhs gias trij cuar A khi x = \(\left(3+2\sqrt{2}\right)^{2015}\cdot\left(3-2\sqrt{2}\right)^{2016}\)
Cho \(x=\sqrt{\dfrac{2-\sqrt{3}}{2}}\) tính giá trị bt:
\(P=\left(2x^5+2x^4-x^3-1\right)^{2016}+\dfrac{\left(2x^3+2x^2-x-3\right)^{2017}}{2x^4+2x^3-x^2-3}\)
