\(\left(2x+7\right)⋮\left(x-2\right)\\ \Rightarrow\left[\left(2x-4\right)+11\right]⋮\left(x-2\right)\\ \Rightarrow\left[2\left(x-2\right)+11\right]⋮\left(x-2\right)\)
Vì \(2\left(x-2\right)⋮\left(x-2\right)\Rightarrow11⋮\left(x-2\right)\Rightarrow x-2\inƯ\left(11\right)\)
Ta có bảng:
x-2 | -11 | -1 | 1 | 11 |
x | -9 | 1 | 3 | 13 |
Vậy \(x\in\left\{-9;1;3;13\right\}\)
\(\Leftrightarrow2x-4+11⋮x-2\)
\(\Leftrightarrow x-2\in\left\{1;-1;11;-11\right\}\)
hay \(x\in\left\{3;1;13;-9\right\}\)