Question

Tìm x: A/ X+5=10-X

B/ 3(4-2)-2(x-1)=x+20

Answer 1

a: x+5=10-x

=>x+x=10-5

=>2x=5

=>\(x=\dfrac{5}{2}\)

b: \(3\left(4-2\right)-2\left(x-1\right)=x+20\)

=>\(3\cdot2-2x+2=x+20\)

=>\(-2x+4-x-20=0\)

=>\(-3x-16=0\)

=>\(-3x=16\)

=>\(x=\dfrac{16}{-3}=-\dfrac{16}{3}\)