Question

Tìm `x`
 

`8^x.`$\text{16}$$^{-2x}$ `=4^5`

Answer 1

\(\Leftrightarrow2^{3x}\cdot2^{-8x}=2^{10}\)

=>-5x=10

hay x=-2

Answer 2

\(2^{3x}.2^{-8x}=2^{10}\\ 2^{3x-8x}=2^{10}\\ 3x-8x=10\\ -5x=10\\ x=-2\)