Question

Tìm x :

 

3(x+5) -3 = 2(x+1) +7

 

15-(x+2)² = -1

 

75-(2x+1)³ =11

Answer 1

a) Ta có: \(3\left(x+5\right)-3=2\left(x+1\right)+7\)

\(\Leftrightarrow3x+15-3=2x+2+7\)

\(\Leftrightarrow3x+12=2x+9\)

hay x=-3

b) Ta có: \(15-\left(x+2\right)^2=-1\)

\(\Leftrightarrow\left(x+2\right)^2=16\)

\(\Leftrightarrow\left[{}\begin{matrix}x+2=4\\x+2=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-6\end{matrix}\right.\)

c) Ta có: \(75-\left(2x+1\right)^3=11\)

\(\Leftrightarrow\left(2x+1\right)^3=64\)

\(\Leftrightarrow2x+1=4\)

hay \(x=\dfrac{3}{2}\)

Answer 2

a) Ta có: $3\left(x+5\right)-3=2\left(x+1\right)+7$

$\iff 3x+15-3=2x+2+7$

$\iff 3x+12=2x+9$

hay x=-3

b) Ta có: $15-{}^{}=-1$

$\iff {}^{}=16$

⇔[x+2=4x+2=−4⇔[x=2x=−6⇔[x+2=4x+2=−4⇔[x=2x=−6

c) Ta có: $75-{}^{}$