Question

tìm x

( 2x +3 ) .( 3-2x) +(2x+3)\(^2\)=0

Answer 1

\(\left(2x+3\right)\left(3-2x\right)+\left(2x+3\right)^2=0\)

\(\left(2x+3\right)\left(3-2x+2x+3\right)=0\)

\(\left(2x+3\right).6=0\)

\(2x+3=0\)

\(2x=0-3\)

\(2x=-3\)

\(x=-\dfrac{3}{2}\)

Vậy \(x=-\dfrac{3}{2}\)

Answer 2

=>(2x+3)(3-2x+2x+3)=0

=>2x+3=0

=>x=-3/2