Bài 1:
\(\left(0,7\right)^3\cdot x=\left(0,49\right)^2\)
=>\(x\cdot\left(0,7\right)^3=\left(0,7\right)^4\)
=>x=0,7
\(x:\left(-0,3\right)^3=\left(0,3\right)^2\)
=>\(x=\left(0,3\right)^2\cdot\left(-0,3\right)^3=\left(-0,3\right)^5\)
Bài 2:
\(4^4=\left(2^2\right)^4=2^8\)
\(3^{20}=\left(3^2\right)^{10}=9^{10};2^{30}=\left(2^3\right)^{10}=8^{10}\)
mà 9>9
nên \(3^{20}>2^{30}\)
\(9^5=\left(3^2\right)^5=3^{10};27^3=\left(3^3\right)^3=3^9\)
mà 10>9
nên \(9^5>27^3\)
Đúng 2
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