a: x/3=y/4 nên x/9=y/12
y/3=z/5 nên y/12=z/20
=>x/9=y/12=z/20=(2x-3y+z)/(2*9-3*12+20)=6/2=3
=>x=27; y=36; z=60
b: 2x/3=3y/4=4z/5
nên \(\dfrac{2x}{3}\cdot60=\dfrac{3y}{4}\cdot60=\dfrac{4z}{5}\cdot60\)
=>40x=45y=48z
=>x/18=y/16=z/15=(x+y+z)/(18+16+15)=49/49=1
=>x=18; y=16; z=15
c: Đặt x/2=y/3=z/5=k
=>x=2k; y=3k; z=5k
xyz=810
=>2k*3k*5k=810
=>30k^3=810
=>k=3
=>x=6; y=9; z=15