Question

Tìm số tự nhiên n sao cho 4n + 13 chia hết cho n + 2

Answer 1

help me guys

 

Answer 2

\(\left(4n+13\right)⋮\left(n+2\right)\\ \Rightarrow\left[4\left(n+2\right)+5\right]⋮\left(n+2\right)\)

Mà \(4\left(n+2\right)⋮\left(n+2\right)\Rightarrow5⋮\left(n+1\right)\Rightarrow n+1\inƯ\left(5\right)=\left\{\pm1;\pm5\right\}\Rightarrow n\in\left\{-6;-2;0;4\right\}\)

Mà \(n\in N\Rightarrow n\in\left\{0;4\right\}\)

Answer 3

help

 

Answer 4

\(\Leftrightarrow n+2=5\)

hay n=3