Question

tìm số nguyên x, biết rằng:

(x-2)² + 5 (x - 2) = 0 

Answer 1

\(\left(x-2\right)^2+5\left(x-2\right)=0\)

=>\(\left(x-2\right)\left(x-2+5\right)=0\)

=>(x-2)(x+3)=0

=>\(\left[{}\begin{matrix}x-2=0\\x+3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-3\end{matrix}\right.\)