Question

Tìm nghiệm của Phương trình Mình cảm ơn ạ

Answer 1

\(4\left(3x-2\right)-\left(3x-2\right)^3=0.\Leftrightarrow\left[4-\left(3x-2\right)^2\right].\left(3x-2\right)=0.\Leftrightarrow\left(2-3x+2\right)\left(2+3x-2\right)\left(3x-2\right)=0.\Leftrightarrow\left(4-3x\right).3x.\left(3x-2\right)=0.\)

\(\Leftrightarrow\left[{}\begin{matrix}4-3x=0.\\3x=0.\\3x-2=0.\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{4}{3}.\\x=0.\\x=\dfrac{2}{3}.\end{matrix}\right.\)

Answer 2

4(3x - 2) - (3x - 2)³ = 0

⇔ (3x - 2)[4 - (3x - 2)² ] = 0

⇔ (3x - 2)(4 - 3x + 2)(4 + 3x - 2) = 0

⇔ (3x - 2)(6 - 3x)(2 + 3x) = 0

⇔ x = \(\dfrac{-2}{3}\) hoặc x = 2