Question

Tìm Min

\(K=\sqrt{x^2+10x+26}+\sqrt{x^2+4x+4}\)

Answer 1

Sửa đề: \(K=\sqrt{x^2+10x+25}+\sqrt{x^2+4x+4}\)

\(=\left|x+5\right|+\left|x+2\right|\)

\(=\left|x+5\right|+\left|-x-2\right|>=\left| x+5-x-2\right|=3\)

Dấu = xảy ra khi -5<=x<=-2