Question

Tìm GTNN Q=x^2 +x +1 Giúp mik với

Answer 1

\(Q=x^2+x+\dfrac{1}{4}+\dfrac{3}{4}=\left(x+\dfrac{1}{2}\right)^2+\dfrac{3}{4}\ge\dfrac{3}{4}\\ Q_{min}=\dfrac{3}{4}\Leftrightarrow x=-\dfrac{1}{2}\)

Answer 2

Q=(x+1)² 
GTNN là Q=0
xảy ra khi (x+1)²=0
                  x+1=0
                  x     =-1