Ta có |2x - 1| \(\ge0\)\(\forall x\)
=> -|2x -1| \(\le0\)
<=> 10 - |2x - 1| \(\le10\forall x\)
Dấu "=" xảy ra <=> 2x - 1= 0 <=> x = 0,5
Vậy Max A = 10 <=> x = 0,5
Ta có:
\(\left|2x+1\right|\ge0\)
\(\Leftrightarrow10-2\left|x+1\right|\le10\)
Dấu '' = '' xảy ra khi: \(2x+1=0\Leftrightarrow x=\frac{-1}{2}\)