\(2x-3y+xy=9\)
\(\Leftrightarrow xy+2x-3y-6=3\)
\(\Leftrightarrow x\left(y+2\right)-3\left(y+2\right)=3\)
\(\Leftrightarrow\left(x-3\right)\left(y+2\right)=3\)
| x-3 | -3 | -1 | 1 | 3 |
| y+2 | -1 | -3 | 3 | 1 |
| x | 0 | 2 | 4 | 6 |
| y | -3 | -5 | 1 | -1 |
Vậy \(\left(x;y\right)=\left(0;-3\right);\left(2;-5\right);\left(4;1\right);\left(6;-1\right)\)
Đúng 1
Bình luận (0)