Question

Tìm \(a\) và \(b\) để hệ :    

                        \(\left\{{}\begin{matrix}ax+by=17\\3bx+ay=-29\end{matrix}\right.\)

có nghiệm là \(\left(x;y\right)=\left(1;-4\right)\).

Answer 1

để hệ phương trình có nghiệm là \(\left(x;y\right)=\left(1;-4\right)\)

\(\Leftrightarrow\left\{{}\begin{matrix}a-4b=17\\3b-4a=-29\end{matrix}\right.\)\(\Leftrightarrow\left\{{}\begin{matrix}a=4b+17\\3b-4\left(4b+17\right)=-29\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}a=4b+17\\3b-16b-68=-29\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}a=4b+17\\-13b=39\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}b=-3\\a=4.\left(-3\right)+17\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}b=-3\\a=5\end{matrix}\right.\)

vậy \(a=5;b=-3\)