Question

Thực hiện các phép tính sau:a)(×-3)^2-(×-4)(×-2) b)×+7/2×-4-×+4/×^2-2×

Answer 1

a: (x-3)^2-(x-4)(x-2)

=x^2-6x+9-x^2+6x-8

=1

b: \(\dfrac{x+7}{2x-4}-\dfrac{x+4}{x^2-2x}\)

\(=\dfrac{x^2+7x-2x-8}{2x\left(x-2\right)}=\dfrac{x^2+5x-8}{2x\left(x-2\right)}\)