\(4+2\sqrt{3}\)
\(=3+2\sqrt{3}+1\)
\(=\left(\sqrt{3}\right)^2+2\cdot\sqrt{3}\cdot1+1^2\)
\(=\left(\sqrt{3}+1\right)^2\)
Ta có:
\(VT=4+2\sqrt{3}\)
\(=1+2\sqrt{3}+3\)
\(=1^2+2\cdot\sqrt{3}\cdot1+\left(\sqrt{3}\right)^2\)
\(=\left(1+\sqrt{3}\right)^2\)
\(=\left(\sqrt{3}+1\right)^2=VP\left(dpcm\right)\)