Question

\(\sqrt{x-2}+\dfrac{1}{3}=1\)

Answer 1

ĐKXĐ: x>=2

\(\sqrt{x-2}+\dfrac{2}{3}=1\)

=>\(\sqrt{x-2}=1-\dfrac{2}{3}=\dfrac{1}{3}\)

=>\(x-2=\dfrac{1}{9}\)

=>\(x=2+\dfrac{1}{9}=\dfrac{19}{9}\left(nhận\right)\)