Question

\(\sqrt{x-2}< 3\)  tim x

 

Answer 1

^{\(\sqrt{x-2}=3\)}

^{\(\sqrt{x-2}=\sqrt{9}\)}

^\(x-2=9\)

\(x=11\)

Vậy x=11

Answer 2

\(\sqrt{x-2}< 3\\ \Rightarrow x-2< 9\\ \Leftrightarrow x< 11\)

vậy....

Answer 3

Có \(\sqrt{x-2}\) < \(3\) ⇒ \(\sqrt{x-2}\) < \(\sqrt{9}\) ⇒ \(x-2\) < \(9\) ⇒ \(x\) < 11

Vậy với mọi \(x\) < 11 thì \(\sqrt{x-2}\) < \(3\)

Answer 4

\(\sqrt{x-2}< 3\)

nên x-2<9

hay x<11

Vậy: \(2\le x< 11\)

Answer 5

xin phép làm lại:

\(\sqrt{x-2}< 3\\ \Rightarrow\left\{{}\begin{matrix}x-2\ge0\\x-2< 9\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x\ge2\\x< 11\end{matrix}\right.\\ \Rightarrow2\le x< 11\)

vậy....