\(ĐK:-\frac{1}{3}\le x\le2\)
\(PT\Leftrightarrow2x+3+2\sqrt{\left(3x+1\right)\left(2-x\right)}=9\)
\(\Leftrightarrow\sqrt{-3x^2+5x+2}=3-x\)
\(\Leftrightarrow\left\{{}\begin{matrix}-\frac{1}{3}\le x\le2\\-3x^2+5x+2=9-6x+x^2\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}-\frac{1}{3}\le x\le2\\4x^2-11x+7=0\end{matrix}\right.\)\(\Leftrightarrow\)\(\left[{}\begin{matrix}x=1\\x=\frac{7}{4}\end{matrix}\right.\)(tm)
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