\(\Leftrightarrow\dfrac{\sqrt{3}}{2}cos3x+\dfrac{1}{2}sin3x=0\)
\(\Leftrightarrow sin\left(3x+\dfrac{\pi}{3}\right)=0\)
\(\Leftrightarrow3x+\dfrac{\pi}{3}=k\pi\)
\(\Leftrightarrow x=-\dfrac{\pi}{9}+\dfrac{k\pi}{3}\)
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