Question

\(\sqrt{2\left(x^2-y^2\right)}\sqrt{\dfrac{3}{x+y}}\) với x>= y > 0                   
rút gọn

Answer 1

Ta có: \(\sqrt{2\left(x^2-y^2\right)}\cdot\sqrt{\dfrac{3}{x+y}}\)

\(=\sqrt{2\left(x^2-y^2\right)\cdot\dfrac{3}{x+y}}\)

\(=\sqrt{\dfrac{6\left(x-y\right)\left(x+y\right)}{x+y}}\)

\(=\sqrt{6\left(x-y\right)}\)