Ta có:
\(\left(\sqrt{12-3\sqrt{7}}-\sqrt{12+3\sqrt{7}}\right)^2\)
\(=12-3\sqrt{7}+12+3\sqrt{7}-2\sqrt{12-3\sqrt{7}}.\sqrt{12+3\sqrt{7}}\)
\(=24-2.\sqrt{12^2-\left(3\sqrt{7}\right)^2}\)
\(=24-2\sqrt{144-63}\)
\(=24-18=6\)
Mặt khác, ta dễ thấy \(\sqrt{12-3\sqrt{7}}-\sqrt{12+3\sqrt{7}}< 0\)
\(\Rightarrow\sqrt{12-3\sqrt{7}}-\sqrt{12+3\sqrt{7}}=-\sqrt{6}\)