=>|2x+5|=5
=>2x+5=5 hoặc 2x+5=-5
=>x=-5 hoặc x=0
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Các câu hỏi tương tự
Chứng minh các đẳng thức sau:
a)\(\sqrt{6+2\sqrt{5}}+\sqrt{6-2\sqrt{5}}=2\sqrt{5}\)
b)\(\sqrt{13+4\sqrt{10}}+\sqrt{13-4\sqrt{10}}=4\sqrt{2}\)
c)\(\sqrt{8\sqrt{3}}-2\sqrt{25\sqrt{12}}+4\sqrt{\sqrt{192}}=0\)
a : dfrac{sqrt{x}-1}{sqrt{x}}+dfrac{2sqrt{x}+1}{x+sqrt{x}}b : left(dfrac{sqrt{x}}{sqrt{x}+4}+dfrac{4}{sqrt{x}-4}right):dfrac{x+16}{sqrt{x}+2}với x ≥ 0 x ≠ 10c : dfrac{sqrt{x}}{sqrt{x}-5}-dfrac{10sqrt{x}}{x-25}-dfrac{5}{sqrt{x}+5}với x ≥ 0 x ≠ 9d : dfrac{sqrt{x}}{sqrt{x}+3}+dfrac{2sqrt{x}}{sqrt{x}-3}-dfrac{3x+9}{x-9}với x ≥ 0 x ≠ 9
Đọc tiếp
a : \(\dfrac{\sqrt{x}-1}{\sqrt{x}}+\dfrac{2\sqrt{x}+1}{x+\sqrt{x}}\)
b : \(\left(\dfrac{\sqrt{x}}{\sqrt{x}+4}+\dfrac{4}{\sqrt{x}-4}\right):\dfrac{x+16}{\sqrt{x}+2}\)với x ≥ 0 x ≠ 10
c : \(\dfrac{\sqrt{x}}{\sqrt{x}-5}-\dfrac{10\sqrt{x}}{x-25}-\dfrac{5}{\sqrt{x}+5}\)với x ≥ 0 x ≠ 9
d : \(\dfrac{\sqrt{x}}{\sqrt{x}+3}+\dfrac{2\sqrt{x}}{\sqrt{x}-3}-\dfrac{3x+9}{x-9}\)với x ≥ 0 x ≠ 9
Rút gọn các biểu thức sau:
a, \(5\sqrt{x}-{(x+10\sqrt{x}+25)(\sqrt{x}-5)\over x-25}\) với 0 ≤ x ≠ 25
b, \({\sqrt{x^2-4x+4}\over x-2}\) với x ≠ 2
giải phương trình
a)\(\sqrt{x-1}+\sqrt{4x-4}-\sqrt{25x-25}+2=0\)
b)\(\sqrt{16x+16}-\sqrt{9x+9}+\sqrt{4x+4}+\sqrt{x+1}=16\)
c)\(\sqrt{4x+20}+\sqrt{x+5}-\dfrac{1}{3}\sqrt{9x+45}=4\)
d)\(\dfrac{1}{3}\sqrt{2x}-\sqrt{8x}+\sqrt{18x}-10=2\)
Gi ải phương trình
a) \(\sqrt{4x-20}+\sqrt{x-5}-\dfrac{1}{3}\sqrt{9x-45}=4\) b) \(\sqrt{2x-1}-\sqrt{8x-4}+5=0\)
c) \(\sqrt{x^2-10x+25}=2\) d) \(\sqrt{x^2-14x+49}-5=0\)
1. Tính : \(\dfrac{12}{4-\sqrt{10}}\)-6\(\sqrt{\dfrac{5}{2}}\)+\(\dfrac{5\sqrt{2}+\sqrt{10}}{\sqrt{5}+1}\)
2,Rút gọn:A=(\(\dfrac{\sqrt{x}}{\sqrt{x}-5}\)-\(\dfrac{5}{\sqrt{x}+5}\)+\(\dfrac{10\sqrt{x}}{25-x}\)):\(\dfrac{3}{\sqrt{x}+5}\)
\(\sqrt{x-1}+\sqrt{4x-4}-\sqrt{25x-25}+2=0\)
\(x+\sqrt{5-4x}=0\)
\(\sqrt{1-2x^2}=x-1\)
1,Tính \(\dfrac{12}{4-\sqrt{10}}-6\sqrt{\dfrac{5}{2}}+\dfrac{5\sqrt{2}+\sqrt{10}}{\sqrt{5}+1}\)
2,Rút gọn:A=\(\left(\dfrac{\sqrt{x}}{\sqrt{x}-5}-\dfrac{5}{\sqrt{x}+5}+\dfrac{10\sqrt{x}}{25-x}\right):\dfrac{3}{\sqrt{x}+5}\)
d) \(x-5\sqrt{x}+6=0\)
e) \(\sqrt{x-1}+\dfrac{3}{2}\sqrt{4x-4}-\dfrac{2}{5}\sqrt{25x-25}=4\)
f) \(\sqrt{x-5}+\sqrt{4x-20}-\dfrac{1}{3}\sqrt{9x-45}=6\)
a)\(\sqrt{25-4\sqrt{10-4\sqrt{15+4\sqrt{3}}}}\)
b)\(\sqrt{14-6\sqrt{5+\sqrt{14+6\sqrt{5}}}}\)
c)