Question

sos giúp với ạ

Answer 1

bài 1:

a: \(\dfrac{-7}{27}+\dfrac{-8}{27}=\dfrac{\left(-7\right)+\left(-8\right)}{27}=-\dfrac{15}{27}=-\dfrac{5}{9}\)

b: \(\dfrac{1}{2}+\dfrac{13}{19}-\dfrac{4}{9}+\dfrac{6}{19}+\dfrac{5}{18}\)

\(=\left(\dfrac{1}{2}-\dfrac{4}{9}+\dfrac{5}{18}\right)+\left(\dfrac{13}{19}+\dfrac{6}{19}\right)\)

\(=\dfrac{9}{18}-\dfrac{8}{18}+\dfrac{5}{18}+1=1+\dfrac{1}{3}=\dfrac{4}{3}\)

c: \(\left(\dfrac{23}{41}-\dfrac{15}{82}\right):\dfrac{15}{41}\)

\(=\dfrac{23\cdot2-15}{82}\cdot\dfrac{41}{15}\)

\(=\dfrac{31}{2}\cdot\dfrac{1}{15}=\dfrac{31}{30}\)

bài 2:

a: \(4\dfrac{1}{3}=\dfrac{13}{3}\)

\(-\dfrac{13}{3}=-\dfrac{39}{9}< -\dfrac{8}{9}\)

mà \(-\dfrac{8}{9}< 0< \dfrac{13}{3}=4\dfrac{1}{3}\)

nên \(4\dfrac{1}{3}>0>-\dfrac{8}{9}>-\dfrac{13}{3}\)

b: -3,39<0

0<1,82<4,77<5,83

Do đó: -3,39<1,82<4,77<5,83

=>5,83>4,77>1,82>-3,39