Ta có :
A = \(\dfrac{\text{y^2 ( x + 1 ) + ( x + 1 ) }}{y^2+1}\) = \(\dfrac{\left(y^2+1\right)\left(x+1\right)}{y^2+1}\) = x+1 (1)
B = \(\dfrac{y^2\left(x-1\right)+2x-x}{y^2+2}=\dfrac{\left(y^2+2\right)\left(x-1\right)}{y^2+2}=x-1\) (2)
Từ (1) và (2)
=> A > B
\(\dfrac{\text{y^2 ( x + 1 ) + ( x + 1 ) }}{y^2+1}\) = \(\dfrac{\left(y^2+1\right)\left(x+1\right)}{y^2+1}\)