Bài 1: Căn bậc hai

HT

rút gọn M=\(\left(\sqrt{6}+\sqrt{2}\right)\left(\sqrt{3}-2\right)\sqrt{\sqrt{3}+2}\)

AT
5 tháng 7 2021 lúc 16:36

\(M=\left(\sqrt{6}+\sqrt{2}\right)\left(\sqrt{3}-2\right)\sqrt{\sqrt{3}+2}\)

\(=\left(\sqrt{3}+1\right).\sqrt{2}.\sqrt{\sqrt{3}-2}.\sqrt{\sqrt{3}-2}.\sqrt{\sqrt{3}+2}\)

\(=\left(\sqrt{3}+1\right)\sqrt{4-2\sqrt{3}}\sqrt{\left(\sqrt{3}-2\right)\left(\sqrt{3}+2\right)}\)

\(=\left(\sqrt{3}+1\right)\sqrt{\left(\sqrt{3}-1\right)^2}.\left(-1\right)=\left(\sqrt{3}+1\right)\left(\sqrt{3}-1\right).\left(-1\right)=-2\)

 

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