nếu thấy đúng thì cho mk một lượt đúng nha
a)\(\frac{4a}{5b}.\frac{15b^2}{16a^3}=\frac{4a.15b^2}{5b.16a^3}=\frac{1.3b}{1.4a^2}=\frac{3b}{4a^2}\)
b) \(\frac{4x}{x^2-4}.\frac{x+2}{16x}=\frac{4x}{\left(x-2\right)\left(x+2\right)}.\frac{x+2}{16x}=\frac{4x.\left(x+2\right)}{\left(x-2\right)\left(x+2\right).16x}=\frac{1.1}{\left(x-2\right).1.4}=\frac{1}{4.\left(x-2\right)}\)