H24

Rút gọn biểu thức

\(A=\dfrac{x^2}{5x+25}+\dfrac{2\left(x-5\right)}{x}+\dfrac{50+5x}{x\left(x+5\right)}\)

NT
15 tháng 11 2023 lúc 23:05

ĐKXĐ: \(x\notin\left\{0;-5\right\}\)

\(A=\dfrac{x^2}{5x+25}+\dfrac{2\left(x-5\right)}{x}+\dfrac{50+5x}{x\left(x+5\right)}\)

\(=\dfrac{x^2}{5\left(x+5\right)}+\dfrac{2\left(x-5\right)}{x}+\dfrac{5x+50}{x\left(x+5\right)}\)

\(=\dfrac{x^3+2\cdot5\left(x-5\right)\left(x+5\right)+5\left(5x+50\right)}{5x\left(x+5\right)}\)

\(=\dfrac{x^3+10x^2-250+25x+250}{5x\left(x+5\right)}\)

\(=\dfrac{x^3+10x^2+25x}{5x\left(x+5\right)}=\dfrac{x\left(x^2+10x+25\right)}{5x\left(x+5\right)}\)

\(=\dfrac{\left(x+5\right)^2}{5\left(x+5\right)}=\dfrac{x+5}{5}\)

Bình luận (0)
H24
15 tháng 11 2023 lúc 23:39

\(A=\dfrac{x^2}{5x+25}+\dfrac{2\left(x-5\right)}{x}+\dfrac{50+5x}{x\left(x+5\right)}\left(ĐKXĐ:x\ne0;x\ne-5\right)\)

\(A=\dfrac{x^2}{5\left(x+5\right)}+\dfrac{2\left(x-5\right)}{x}+\dfrac{50+5x}{x\left(x+5\right)}\)

\(A=\dfrac{x^2.x}{5x\left(x+5\right)}+\dfrac{2.5\left(x+5\right)\left(x-5\right)}{5x\left(x+5\right)}+\dfrac{5\left(50+5x\right)}{5x\left(x+5\right)}\)

\(A=\dfrac{x^3}{5x\left(x+5\right)}+\dfrac{10.\left(x^2-25\right)}{5x\left(x+5\right)}+\dfrac{250+25x}{5x\left(x+5\right)}\)


\(A=\dfrac{x^3}{5x\left(x+5\right)}+\dfrac{10x^2-250}{5x\left(x+5\right)}+\dfrac{250+25x}{5x\left(x+5\right)}\)

\(A=\dfrac{x^3+10x^2-250+250+25x}{5x\left(x+5\right)}\)

\(A=\dfrac{x^3+10x^2+25x}{5x\left(x+5\right)}\)

\(A=\dfrac{x\left(x^2+10x+25\right)}{5x\left(x+5\right)}\)

\(A=\dfrac{\left(x+5\right)^2}{5\left(x+5\right)}\)

\(A=\dfrac{x+5}{5}\)

Bình luận (0)