Question

rút gọn biểu thức sau: B=\(\dfrac{3x-4}{x-2\sqrt{x}}-\dfrac{\sqrt{x}+2}{\sqrt{x}}+\dfrac{\sqrt{x}-3}{2-\sqrt{x}}\) với x\(\ge\)0; x≠4

Answer 1

\(B=\dfrac{3x-4-x+4-x+3\sqrt{x}}{\sqrt{x}\left(\sqrt{x}-2\right)}=\dfrac{x-3\sqrt{x}}{\sqrt{x}\left(\sqrt{x}-2\right)}=\dfrac{\sqrt{x}-3}{\sqrt{x}-2}\)