Question

Quy đồng 1/(x ^ 2 + 8x + 15)  va 1/(x ^ 2 + 6x + 9)

Answer 1

\(\dfrac{1}{x^2+8x+15}=\dfrac{x+3}{\left(x+3\right)^2\left(x+5\right)}\)

\(\dfrac{1}{x^2+6x+9}=\dfrac{x+5}{\left(x+5\right)\left(x+3\right)^2}\)