Question

Phân tích thành nhân tử

5/ x³+6x²y+9xy²-4x

Answer 1

`x^3 + 6x^2y + 9xy^2 - 4x`

`= x(x^2 + 6xy + 9y^2) - 4x`

`= x(x+3y)^2 - 4x`

`= x[(x + 3y)^2 - 4]`

`=x[(x + 3y)^2 - 2^2]`

`= x(x+3y - 2)(x+3y+2)`

Answer 2

\(x^3+6x^2y+9xy^2-4x\\ =x\left(x^2+6xy+9y^2-4\right)\\ =x\left[\left(x+3y\right)^2-2^2\right]\\ =x\left(x+3y-2\right)\left(x+3y+2\right)\)