Question

phân tích đa thức thành nhân tử

6x² -12x-7x=14

Answer 1

giúp toi

Answer 2

\(6x^2-12x-7x+14\)

\(=6x\left(x-2\right)-7\left(x-2\right)\)

\(=\left(x-2\right)\left(6x-7\right)\)

Answer 3

Answer 4

6x² - 12x - 7x = 14

<=> 6x² - 19x - 14 = 0

<=> 6x² - 12x - 7x - 14 = 0

<=> 6x(x - 2) - 7(x - 2) = 0

<=> (6x - 7)(x - 2) = 0

<=> \(\left[{}\begin{matrix}6x-7=0\\x-2=0\end{matrix}\right.\)

<=> \(\left[{}\begin{matrix}x=\dfrac{7}{6}\\x=2\end{matrix}\right.\)

Answer 5

Sorry, do mik nhìn sai đề

Answer 6

6x² - 12x - 7x + 14

= 6x(x - 2) - 7(x - 2)

= (6x - 7)(x - 2)

Answer 7

=6x²-12x-7x+14

=6x(x-2)-7x+7.2

=6x(x-2)-7(x+2)

=6x(x-2)+7(x-2)

=(x-2)(6x+7)