Câu hỏi của Trần Minh Hiếu

Question

Phân tích đa thức thành nhân tử:1. $x\left(x+1\right)\left(x+2\right)\left(x+3\right)+1$ 2. $4x^4+1$ 3. $4x^8+1$

Nguyễn Lê Phước Thịnh · Accepted Answer

1: $=\left(x^2+3x\right)\left(x^2+3x+2\right)+1$$=\left(x^2+3x\right)^2+2\left(x^2+3x\right)+1$$=\left(x^2+3x+1\right)^2$2: $=4x^4+1+4x^2-4x^2$$=\left(2x^2+1\right)^2-\left(2x\right)^2$$=\left(2x^2-2x+1\right)\left(2x^2+2x+1\right)$Câu trả lời: 1: $=\left(x^2+3x\right)\left(x^2+3x+2\right)+1$$=\left(x^2+3x\right)^2+2\left(x^2+3x\right)+1$$=\left(x^2+3x+1\right)^2$2: $=4x^4+1+4x^2-4x^2$$=\left(2x^2+1\right)^2-\left(2x\right)^2$$=\left(2x^2-2x+1\right)\left(2x^2+2x+1\right)$

Tiến Thi · Answer

1: =(x2+3x)(x2+3x+2)+1=(x2+3x)(x2+3x+2)+1=(x2+3x)2+2(x2+3x)+1=(x2+3x)2+2(x2+3x)+1=(x2+3x+1)2=(x2+3x+1)22: =4x4+1+4x2−4x2=4x4+1+4x2−4x2=(2x2+1)2−(2x)2=(2x2+1)2−(2x)2=(2x2−2x+1)(2x2+2x+1)Câu trả lời: 1: =(x2+3x)(x2+3x+2)+1=(x2+3x)(x2+3x+2)+1=(x2+3x)2+2(x2+3x)+1=(x2+3x)2+2(x2+3x)+1=(x2+3x+1)2=(x2+3x+1)22: =4x4+1+4x2−4x2=4x4+1+4x2−4x2=(2x2+1)2−(2x)2=(2x2+1)2−(2x)2=(2x2−2x+1)(2x2+2x+1)

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