Question

(n+5) chia hết cho (n+1)

tìm số tự nhiên x

giúp mik

Answer 1

Answer 2

\(\left(n+5\right)⋮\left(n+1\right)\)

\(\Rightarrow\left(n+1\right)+4⋮\left(n+1\right)\)

\(\Rightarrow4⋮\left(n+1\right)\Rightarrow\left(n+1\right)\inƯ\left(4\right)=\left\{1;-1;2;-2;4;-4\right\}\)

Do \(n\in N\)

\(\Rightarrow n\in\left\{0;1;3\right\}\)

 

Answer 3

(n+5)⋮(n+1)(n+5)⋮(n+1)

⇒(n+1)+4⋮(n+1)⇒(n+1)+4⋮(n+1)

⇒4⋮(n+1)⇒(n+1)∈Ư(4)={1;−1;2;−2;4;−4}⇒4⋮(n+1)⇒(n+1)∈Ư(4)={1;−1;2;−2;4;−4}

Do 

Answer 4

Answer 5

x nào

 

Answer 6

Ta có: \(n+5⋮n+1\)

\(\Leftrightarrow n+1\in\left\{1;-1;2;-2;4;-4\right\}\)

hay \(n\in\left\{0;-2;1;-3;3;-5\right\}\)